m_p7 Posted April 22, 2005 Share Posted April 22, 2005 I shot a couple sheets of 4x5 Delta100 in a pinhole camera. Metering gave me 8 minutes at f/256. I doubled that for reciprocity as a guess, but after looking at the reciprocity chart, I realized that I'm probably still several stops underexposed. Anyone have some suggestions for getting the most speed and a useful negative from this? I was leaning toward DDX for 30 minutes (from digitaltruth.com's 2.5x factor for a 3 stop push with comp. dev.), but I also have Xtol, Rodinal, HC110, Ilford HC, Tmax, and Microphen developers handy. Any suggestions appreciated. I'm more interested in film speed at the expense of grain if that helps, since I won't enlarge this much at all. TIA -Mike Link to comment Share on other sites More sharing options...
anupam Posted April 22, 2005 Share Posted April 22, 2005 Looking at the exposure table from the PinholeDesigner, your time looks about 10 stops underexposed. That would be quite a push. Haven't looked at the reciprocity chart for Delta 100, though. Link to comment Share on other sites More sharing options...
nige_buddy Posted April 23, 2005 Share Posted April 23, 2005 I must be missing some text in the 1st post.. nowhere does it say how much light was 'about' so how can you say it was "10 times underexposed" . I have a f200 bodycap pinhole and it's documentation suggests 4secs at f240 for 100asa and when I've used it density has been fine. I was fine-tuning my 8x10 pinhole with paper negs today and with f288 I got good exposure for paper (asa of 4-6) of 2minutes (metered at 1/125 @ f16 for 400asa). So, it must have been a fair bit less than 'Sunny-16' to warrent 8min for 100asa or somethings a miss with your calcs. Link to comment Share on other sites More sharing options...
anupam Posted April 24, 2005 Share Posted April 24, 2005 <i>nowhere does it say how much light was 'about' so how can you say it was "10 times underexposed"</i> <p>The post does say that the correct exposure was 8 mins @ f250 without reciprocity correction. You need no further information about the light, unless you are assuming that MP made a mistake in calculating exposure. <p>Now if you look at the chart WITH the reciprocity factored in, you will see that 8 min is the equivalent of about 1/2 a sec. Well, its not exactly 10 stops but you can calculate the amount of underexposure from there.<p>-A Link to comment Share on other sites More sharing options...
m_p7 Posted May 10, 2005 Author Share Posted May 10, 2005 Well, I finally got around to processing that stuff, and after I thought about it and looked at the pinhole designer program (thanks for that, BTW), it looks like I was about 5-6 stops under. Here are the results, hopefully you can read the text in the shot; I had to keep the size down so the pic would display in the thread.<div></div> Link to comment Share on other sites More sharing options...
m_p7 Posted May 10, 2005 Author Share Posted May 10, 2005 Shots are from Muir Woods in California, BTW. Link to comment Share on other sites More sharing options...
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