weasel_bar Posted September 11, 2022 Author Share Posted September 11, 2022 Oops. I made a typo. I meant: "Therefore, the slope of the curve, if linear, from log(Hm) to log(exposure where density 0.8 above Hm) = (0.9-0.1) / 1.3 = 0.6." Link to comment Share on other sites More sharing options...
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