BelaMolnar Posted January 27, 2009 Posted January 27, 2009 <p>Hi everybody there. My question is, I like to buy a cosmetically very good Nikon lens; AF 28-70mm f/3.5-4.5D , but the lens blades has oil on it. The price is very attractive, I my get it for 10 or 20 dollar plus shipping. How much would be the cost to repair it, or some home made solution.? I'm an electrical and mechanical engineer, and a very good handyman, all ready repaired some very fine instruments, etc. Or! It is an-repairable, or just don't bother. Thank you for your advise.</p>
wpahnelas Posted January 27, 2009 Posted January 27, 2009 <p>$10-20 is a good deal, but pay the extra $$ to get one in good working order. oil on the blades is the reason for the "discount." i paid about $70 for mine, and was very satisfied. </p>
dan_brown4 Posted January 27, 2009 Posted January 27, 2009 <p>It's not so much the money ($20 + repair), but the hassle of getting it done. I'd go to KEH and pay $100 to get a good sample the easy way (actually, that is what I did to get mine).</p>
Michael R Freeman Posted January 27, 2009 Posted January 27, 2009 It's certainly repairable, but as others have noted good copies of this lens are not very expensive, and not hard to find. If you have to pay someone to do the repair, it will easily cost more than the purchase price of a good copy. Repairing it yourself is an option, but you could be getting into a real jackpot if you haven't opened up an autofocus zoom before (particularly one with both a "D" encoding strip and a focal length encoding strip). I have actually opened up this particular model (for parts, so I didn't have to worry about putting it back together). Some of the major assemblies are secured together with adhesive tape, but getting to both sides of the diaphragm could require some major disassembly. I don't remember if it's possible to remove the front and rear optical groups to get access to the diaphragm without opening up the rest of the lens. Maybe, maybe not?
BelaMolnar Posted January 27, 2009 Author Posted January 27, 2009 <p>Thank you for your advise, for all of you.</p>
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