mike_davis17

Better late than never (this post), but months later, Sony still hasn't fixed this problem. I struggled for almost three hours to spend $9.99 ,

but Sony's website wouldn't take my money from PayPal or Visa, on multiple PCs and browsers.

Here's the solution: Buy a Playstaion Gift Card on Amazon. You'll receive a voucher code by email that can then be used at the lame

Sony page to add money to your Sony account wallet. Then turn on your camera and download the app! The wallet will be debited.

<p>Hi Bob,</p>

<p>Relative to the 56mm frame width of your 6x6 body or the 65mm frame width of your XPAN, the E-M1's 17.3mm sensor has only 30.9% or 26.6% of those widths, respectively.</p>

<p>Shooting the 6x6 at f/16 would be like shooting the E-M1 at f/4.9, in terms of diffraction and DoF for an equivalent focal length. (f/4.9 is 30.9% of f/16; you're opening up 3 and 1/3 stops.)</p>

<p>Shooting the XPAN at f/16 would be like shooting the E-M1 at f/4.3, in terms of diffraction and DoF for an equivalent focal length. (f/4.3 is 26.6% of f/16; you're opening up 3 and 2/3 stops.)</p>

<p>In summary, you'll find the smaller sensor giving you the same DoF and diffraction for a given print size and viewing distance, at shutter speeds that are more than eight times faster (corresponding with opening up more than 3 stops in each comparison).</p>

<p>Are your E-M1 primes three 3 and 1/3 or 3 and 2/3 stops faster than your 6x6 and XPAN primes? </p>

<p>Mike</p>

<p>If I'm interpreting Patrick Gainer's posts correctly, for Delta 100, where A = 0.046 and B = 1.62,<br>

Log(tc -tm) = Log(0.046) + 1.62Log</p>

<p>Solving for tc, we get:<br>

tc = 0.46tm^1.62 + tm</p>

<p>or<br>

Adjusted Exposure = 0.46*(x^1.62)+x<br>

where x = Measured Exposure</p>

<p>or<br>

Adjusted Exposure = 0.46*(Measured Exposure^1.62)+Measured Exposure</p>

<p>Thanks Patrick!<br>

Mike</p>

<p> </p>