dweezil Posted May 1, 2008 Share Posted May 1, 2008 Hi, <p> I have recently aquired the Arsat/ Zodiak 30 mm fisheye and since I have nomanual<p> I was wondering what the needed compensation is for the various filters that aredelivered with the lens.<p> I've searched and can't seem to find anything about this.<p> Regards,<p> Erwin<p> Link to comment Share on other sites More sharing options...
q.g._de_bakker Posted May 1, 2008 Share Posted May 1, 2008 You do not have the manual, but you do have the filters themselves, right?<br>Have a look at what it says on their rims.<br><br>The factors you'll find printed there are aperture factors, with "1.4x" being equal to a "2x" shutterspeed factor, or 1 stop, and "2.8x" being equal to a "4x" shutterspeed factor, or 2 stops. Link to comment Share on other sites More sharing options...
dweezil Posted May 1, 2008 Author Share Posted May 1, 2008 I bought the lens 2nd hand and it came in a case with the filters but no manual and I could not find one on the net. I had seen the markings on the filters but could not figure it out. thanks for the info. Link to comment Share on other sites More sharing options...
richard_p Posted May 1, 2008 Share Posted May 1, 2008 A 2 factor is equal to 2 f stops (4x). A 2.8 factor equals to 3 f stops (8x). Richard Link to comment Share on other sites More sharing options...
q.g._de_bakker Posted May 2, 2008 Share Posted May 2, 2008 ???<br>That's not right either. ;-)<br><br>The measured values (i hadn't put them in front of a meter before) are closer to an interpretation of the factors as being shutterspeed factors after all.<br>The "1.4x" printed on the filter then corresponds to 0.5 stop, the "2.8x" factor to 1.5 stop.<br><br>A factor will never equal the number of stops, Richard.<br>Unless you assume that they didn't mean the figures to represent factors to begin with, and the little "x" they put behind the figure on the rims is there in mistake.<br>So a factor of 2.8 either equals log(2.8)/log(1.4) = 2 stops (with 1.4x being the step size separating two aperture stops) or log(2.8)/log(2) = 1.485... stops (2 being the step size separating two shutterspeed stops). Link to comment Share on other sites More sharing options...
johan_de_groote Posted May 2, 2008 Share Posted May 2, 2008 Thanks for that info. I also bought one last weekend. Really a wonderfull lens. Link to comment Share on other sites More sharing options...
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