bernard_wiessner1 Posted November 15, 2005 Share Posted November 15, 2005 Does anyone know what the ground level difference in linear feet would be between a 105mm lens and a 135mm lens? Thanks to all. Link to comment Share on other sites More sharing options...
oceanphysics Posted November 15, 2005 Share Posted November 15, 2005 I'd say almost six linear feet above ground level when the camera it's attached to is up to my eye, or four linear feet above ground level when it's hanging around my neck on a strap. What in the world are you asking? Link to comment Share on other sites More sharing options...
frank_skomial Posted November 15, 2005 Share Posted November 15, 2005 Not being able to answer this quastion kind of upsets me... Perhaps the difference between 135 - 105 mm is 30 mm, or 3 cm. If you want this in feet, then if 1 foot at ground level has about 30 cm, so the answer could be 1/10 of foot. Then again.. this could be true but only at the ground level, otherwise it can be totally wrong. Link to comment Share on other sites More sharing options...
frank uhlig Posted November 15, 2005 Share Posted November 15, 2005 Well, 135mm minus 105mm is 30 mm difference, or (an inch is about 25mm) 1 1/4 inches, or 1/10 of a linear foot (12 inches to a foot). If that is what you were wondering. But that makes as little sense as your question does to me. Whose ground level, what has that to do with anything ... ? photographic? Good luck sorting this one out, Bernard! Link to comment Share on other sites More sharing options...
SCL Posted November 15, 2005 Share Posted November 15, 2005 Bernard - would you care to explain your question...as it stands it makes no sense whatsoever. Link to comment Share on other sites More sharing options...
bernard_frank Posted November 15, 2005 Share Posted November 15, 2005 I think what Bernard means is how many feet would you have to walk towards your subject to get the same crop with the 135 as with the 105. Am I right, Bernard? Now, I'm sorry but I don't have the answer :) Link to comment Share on other sites More sharing options...
david_h._hartman Posted November 15, 2005 Share Posted November 15, 2005 Maybe what he is interested in is image or lens magnification? If not I don't have a clue what he's on about. Link to comment Share on other sites More sharing options...
NetR Posted November 15, 2005 Share Posted November 15, 2005 >I think what Bernard means is how many feet would you have to walk towards your subject to get the same crop with the 135 as with the 105. That's what I think Bernard means too. The geometry is linear, so you would need to be 105/135 as far away to get the same image size with a 135mm lens as you would with a 105mm lens = 78% as far, so you move in 22% closer. How far that is depends on how far away the subject is. For a subject at infinity, 22% of infinity is still a long walk ;-) For many optical purposes infinity is about 10m, so around 8m would be equivalent, but it depends very much on your subject and desired depth of field. Regards, Ross Link to comment Share on other sites More sharing options...
b2 - Posted November 15, 2005 Share Posted November 15, 2005 If BF is right (and I think he is), you need to keep in mind that the difference will change as your initial distance from the subject changes. I think it's a percentage of the distance perhaps. Just for example (these are NOT the right numbers)! Lets say that at 10 feet with a 135, you need to go to 11 feet with a 105. But at 20 feet it might be 22, and at 5, it might be 5 1/2. Just guesses. Perhaps someone out there with a 80-200 sitting around and a few seconds (and a tape measure) could find out for us. Come on, some one has to have that grand old KING of the zooms (I made the mistake of selling the one I had back to my brother-inlaw with the F3 a few years back, UGH!). B2 (;-> Link to comment Share on other sites More sharing options...
anupam Posted November 15, 2005 Share Posted November 15, 2005 The galleries have a photo of the week. The forums should have a riddle of the week. Link to comment Share on other sites More sharing options...
rob_murray Posted November 15, 2005 Share Posted November 15, 2005 It might be easier to buy a zoom lens instead.. or walk a couple steps closer using the 105 lens or use the 135 lens and take a couple steps back...my head hurts now.... Link to comment Share on other sites More sharing options...
david_h._hartman Posted November 16, 2005 Share Posted November 16, 2005 If one is shooting portraits, one typical use of these lenses, you shoot from about 2 meters and the perspective is the same as your point of view or subject to lens is the same. The difference is you get a head and shoulders portrait with the 105mm lens and a tight head shot with the 135mm.<br> <br> My preference on film is the 105/2.5 AIS but I own a 135/2.8 AIS also. They are sufficiently different for my purposes.<br> <br> The 135/2.8 AIS makes a great medium telephoto on the DX formats. With the D2H its about like a 210mm lens on film, about like a 205mm on the D2X.<br> <br> Regards,<br> <br> Dave Hartman. Link to comment Share on other sites More sharing options...
briany Posted November 16, 2005 Share Posted November 16, 2005 It really is a stunning question.. "whatchu talkin bout, Willis?" <br> <a href="http://home.aut.ac.nz/staff/rvink/nikon.html"> http://home.aut.ac.nz/staff/rvink/nikon.html</a><br> If you're talking about the AF DC versions and lay them on their side, the 105 is 111mm, and the 135 is 120mm, so the difference in linear feet would be 9/25.4/12 = .0295 linear feet. Linear feet, mind you.. if you want board feet, it's a whole 'nother story.... Link to comment Share on other sites More sharing options...
david_h._hartman Posted November 16, 2005 Share Posted November 16, 2005 <em>It might be easier to buy a zoom lens instead.. or walk a couple steps closer using the 105 lens or use the 135 lens and take a couple steps back...my head hurts now.... --Rob Murray<br> </em><br> This depends on what you want. If the perspective is important or the relationship and size of background objects zooming and walking are different. When you zoom in the perspective says the same as the angle of view gets tighter. You take in less of the background. When you walk and the focal length is constant the point of view changes and so does the perspective.<br> <br> If you move back and use a longer focal length you take in less background. A slight change in position, left or right, may allow considerable selection of background properties with telephotos. For example you might avoid a confusing background or select a dark or light background for contrast with your subject.<br> <br> The bokeh (excuse me ;-) of the 105/2.5 AIS and 135/2.8 AIS is quite similar wide open but the size of the blobs will be larger with the 135/2.8. I dont know where it is now but I did an experiment with a nasty little point light source background hot spot. The lenses were focused at 2m while the light, a bare AAA Mini-Mag flashlight (as a candle) was at 5m. There are comparison photos lost in the archives. <br> <br> There are different esthetic possibilities available with just a change form 105mm to 135mm. I prefer manual focus primes if I will be shooting a number of shots at one distance with one focal length. To me they just handle better. I also love my AF zooms where things are more random. The primes are great for high flare situations. My 80~200/2.8D ED AF Zoom-Nikkor isnt nearly as graceful when turned towards the sun as my 105/2.5 AIS.<br> <br> Its often been said that you can learn more about perspective with prime lenses. I disagree, I think one can learn equally well with either primes or zooms provided that they know that its the point of view, not the focal length that make the difference.<br> <br> Regards,<br> <br> Dave Hartman. Link to comment Share on other sites More sharing options...
b2 - Posted November 16, 2005 Share Posted November 16, 2005 ..... The bokeh (excuse me ;-) .... God Bless You B2 (;-> Link to comment Share on other sites More sharing options...
ilkka Posted November 16, 2005 Share Posted November 16, 2005 Lot of good answers to a question nobody understands. Link to comment Share on other sites More sharing options...
gaius1 Posted November 16, 2005 Share Posted November 16, 2005 Download <a href="http://tangentsoft.net/fcalc/win32.html">f/Calc</a>. Link to comment Share on other sites More sharing options...
csuzor Posted November 16, 2005 Share Posted November 16, 2005 That is great little program Guy, thanks. Along with the online DOF plotter, both are indispensible. Link to comment Share on other sites More sharing options...
bernard_frank Posted November 16, 2005 Share Posted November 16, 2005 I love this forum! BTW, where has Bernard Wiessner gone? Link to comment Share on other sites More sharing options...
Ed_Ingold Posted November 16, 2005 Share Posted November 16, 2005 This undecipherable question had the same effect as a bad packet on the internet - blue screen - dump everything you know. Link to comment Share on other sites More sharing options...
alex_lofquist Posted November 16, 2005 Share Posted November 16, 2005 D=cosh height(ft) x FL/DOF x T (in degrees kelvin) x coeff of linear expansion for each mile above the center of the earth. This applies strictly for only land forms. If the photographer uses the left eye the correction is small but noticeable. Variation in latitude affect the corliolis force and require an additional correction. A GPS is advised here! Link to comment Share on other sites More sharing options...
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