mix a gallon of c41 developer with 3.5gallon kit?

[wing_gee]

I shot a roll of 120 in a cheapy fuji rangefinder over the weekend.

 

I'm getting ready to do my first roll on the processor tommorow. I

stopped by my local camera place and picked up a 3.5g developer kit,

1gallon bleach, fixer mix. They didn't have any replenisher for the

developer and bleach in stock.

 

My question is how hard would it be to mix a gallon worth of

chemistry? or should I mix all 3.5g and fill it using 1 gallon jugs.

replenishing with the mixed chemistry?

 

Since I don't have any replenisher for the bleach and developer, I'm

just trying to find a way of using these chemicals economically. I

guess worse case scenario is one shot it all, but it seems like a

waste.

 

suggestions or thoughts?

 

Thanks!

Wing

[don_cooper]

Haven't done it for a couple of years (digital now) but I never mixed the full 3.5 gallons. In fact I only mixed what I needed for that particular batch. Never had a problem. You do however need to measure the contents and calculate out the mixes. If you'd like I'll send you my calculations via Email if you want to save some work.

[discpad]

You can mix up the whole 3.5 gallons and freeze, or mix up liter or gallon quantities per Kodak CIS-49. Go to my Home Page at:

http://users.snip.net/~joe/default.htm

and download my C-41 process manual Z-131 "PDF binder" -- You'll find CIS-49 spliced in between chapters 1 & 2 (PDF page 19).

[wing_gee]

Thanks Dan!<br><br>

 

So according to the cis-49 article. Can we double check my math to make 1 gallon with a 3.5G kit? <br><br>

 

The table shows amount to make 1L of chemistry with a 3.5 Gallon kit. Starting water is 750ML, Part A is 73.6, Part B is 8.67ML, and Part C is 8.91ML.<br><br>

 

We need 1 Gallon so we multiply everything by 3.785L<br><br>

 

Starting water: 3.785L x 750ML = 2837.75ML = 2.84L<br>

Part A: 73.6ML x 3.785L = 278.576ML = 279ML<br>

Part B: 8.67ML x 3.785L = 32.81ML = 33ML<br>

Part C: 8.91ML x 3.785L = 33.72ML = 34ML<br><br>

 

So we have:<br>

Starting Water: 2.84L<br>

Part A: 279ML<br>

Part B: 33ML<br>

Part C: 34ML<br>

Add enough water to make 1 gallon.<br><br>

 

That seems like it's going to be difficult measure 33ML and 34ML.<br><br>

 

Does this look correct?

<br><br>

Thanks!<br>

Wing

[g._armour_van_horn]

Why make yourself nuts trying to hit some magic number? Why not just divide all the quantities by four, yielding .875 gallons, or by two for 1.75 gallons?

 

Doing it your way you're going to get three 1-gallon mixes and then one half-gallon mix. And for that half-gallon mix, you really don't want to just take what was left after measuring out your odd quantities three times and trusting that the remains will actually make any semblance of what the developer was supposed to be.

 

Van

[g._armour_van_horn]

Allow me to expand on that last comment. You have three concentrates here, and when all dumped in with the right batch of water you'll have 3.5 gallons of a good mix. Let's assume that their tolerance for filling those three bottles is +/- 2ml.

 

Now, you remove some quantity of each concentrate to make each of your one-gallon batches. Let's assume that you, also, can hold +/- 2ml tolerance on measurements on each of those three batches.

 

When you're down to the last batch, the accuracy of the remaining quantities of each concentrate is +/- 8ml. That's right, the original factory tolerance plus your own applied three times. And what now that tolerance is being applied to 1/7 the total volume. That means that the accuracy of the factory mix is 28 times the accuracy of what you would get by just dumping the end of each bottle in.

 

So don't go there, measure every batch.

 

Van