colin_fischer

<p>I love this site for this 1 feature alone <a href="http://www.the-digital-picture.com/Reviews/ISO-12233-Sample-Crops.aspx?Lens=104&Camera=452&Sample=0&FLI=3&API=0&LensComp=456&CameraComp=452&SampleComp=0&FLIComp=4&APIComp=0">http://www.the-digital-picture.com/Reviews/ISO-12233-Sample-Crops.aspx?Lens=104&Camera=452&Sample=0&FLI=3&API=0&LensComp=456&CameraComp=452&SampleComp=0&FLIComp=4&APIComp=0</a><br>

The devil is in the details as they say, and you should be able to pretty easily tell the difference in the details, especially mid and centre when you get into the very fine lines.<br>

Edited the link so the comparison uses the same camera body.</p>

<p>Can anyone tell me if a standard size B+W UV filter will cause vignetting with the 16-35L on a full frame camera? I was in my local shop today and I was looking at getting the B+W thin UV filter but they didn’t have it in multi-coat. The guy helping me suggested the normal size filter would work with out any problems but I frankly wasn’t sure if I believed him.</p>

<p>Sadly I don't have the answer, but instead have more wood for the fire as it were. I was going to post my own post but I may as well piggy back yours as you may benifit from it as well. I also have a recently purchased a 72mm diameter lense (Canon 24-105 4L). I have a UV for it but haven't yet picked up a Circular Polarizer. I know that the next lense I want to buy is the Canon 16-35 2.8L which has an 82mm diameter. Does it make sense to get an 82mm filter and use a step up ring on my 77mm lenses when I want to use my polarizer? As far as I can tell thats the reason for the step up rings but is there some hidden gotcha that I don't know about regarding them?</p>

<blockquote>

<p>I remember reading something in the manual about having sufficient battery power prior to trying to clean your sensor.</p>

</blockquote>

<p>I always thought this was because if the battery runs out the mirror will come back down and you could damage it if you happen to have anything in the camera that could be hit by the mirror.</p>

 

<p>Its a canon 8800F and the specs for it are<br>

 

<table border="1">

<tbody>

<tr valign="top">

<td width="196"><strong>Max. Resolutions:</strong></td>

<td width="388">Optical: 4800 x 9600 dpi<br />Interpolated: 19,200 x 19,200 dpi</td>

</tr>

</tbody>

</table>

<br>

Thanks for all your input guys.</p>

<p>My scanners optical resolution (not interpolated) is 4800 X 9600 dpi, the problem I run into is that when I try to scan 16 bit color at 9600 the twain driver tells me I<br />Scanning cannot be performed unless the crop size output size or output resolution is reduced to 10000 X 30000 pixels or less.<br />The other downside is that at 9600/16 bit each negative ends up at around 700mb (raw).<br />Between me starting this post and finishing it I did a bunch of research on how the scanner resolutions are rated and it appears they get the second number by 1/2 stepping the linear vertical distance to achieve the 9600 portion of the Max resolution specification so from my thinking scanning at anything over 4800 is just a waste of time and disk space. I am correct in this?</p>

<p>I have recently started a project of scanning in all my old negatives (don't worry I am not throwing them out once I am done or anything like that, but god forbid if the house burns down or something like that this way I atleast have digital copies in the fire safe and I can tag them nicely so in 30 years I know who is in the pictures). Anyways after playing around with the scanner settings I can't decide if I should go 8 bit per channel color or 16 bit per channel color. The problem is that if I go to 16 I have to drop my DPI from 9600 down to 6400 and I am not sure if it's worth the trade off. I have done a couple various test scans and compared the 2 settings and to my eyes the higher DPI lower bit rate seem to look better. I just don't want to get 6 months into it and find out some obvious reason that I should have went the other way and want to start over again because I made the wrong choice.<br>

Thanks for any input</p>