28mm on a 10D

I've read in many reviews and discussions about the sensing area

smaller than 35mm in the 10D and other DSLRs causing a 'telephoto'

effect on lenses.

 

I'm not very good at math, but can someone explain to me how the

equivalent calculation of mm can be done? For example, what would a

28mm lens be on the 10D?

 

Also, is the chip size different between the D30 and D60? Any insight

into this will be much appreciated.

For everything but a fisheye, you just multiply the focal length by 1.6, e.g. 28*1.6 is around 45, so a 28mm on a 10D gives you similar framing to a 45mm on a full-frame digital or 35mm film camera. Chip size is the same between the D30, D60, and 10D, but different for the 1D and 1Ds.

I own a 10D, and I use the tamron 19-35mm lens. This effectivly gives me 30.4mm. This was as close to 28mm that I could get without breaking the bank! If you can afford a lens like Canon's 17-40mm, that will get you down to 27.2mm. I recommend the DSLRs. Good luck!