Working out lux/watts output equivalents

<p>Hey,</p>

<p>I was wondering if anyone on the forum might be able to help with a problem I'm trying to get to the bottom of.</p>

<p>I've been using this <a href="https://www.amazon.co.uk/Neewer%C2%AE-Camera-Photo-Dimmable-Fluorescent/dp/B00U8H2EYK">ring light</a> for various photo/video projects, but if possible want to find something with a bit more throw and output power.</p>

<p>I recently came across <a href="http://www.fvlighting.com/z720-ultracolor-led-ring-light.html">F & V's Z720 light</a> which looks good, seems to offer a more flexible and better quality light source, and is described as having a power draw of 57.6 watts and a lux of 3010. My current light is listed is having a 75watt/600w incandescent equivalent, so seemingly two separate measurements for different types of light - which is fair enough, I realise these things might not be directly comparable - but is there any way of working out within this (or even get a sense of) if the Z720 might offer more power/throw, or not? (or even anything I can test on my light to try and work this out).</p>

<p>Would be pretty crushing to spendin the region of £800 for an upgrade only to find it didn't do what you had hoped, or worse still underperformed the item it was intended to replace.<br /> <br /> Any input very gratefully received!</p>

<p>If the specs on the Z720 is correct you will get this.<br>

Put an incident meter at 1 meter in front of the light. It should read EV10.2 @ ISO 100 or 1/60 sec f/4 to f/5.0 or so with ISO 100. If you don't have an incident meter substitute a gray card and read it with you camera. You can do this with your light and if your light read higher then it's not an upgrade.</p>

<p>Hey BeBu,<br>

Many thanks, that sounds like a good practical way of working this out - will give that a go.</p>

<p>The link you provide to the data says the unit give 3010lx at 1 meter.<br>

It is a ISO 100, t:1/60, f: 4.3 at 1 meter from lamp.<br /><br />¿What is the f, t you get with your current lamp?</p>